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		<title>G.I.S Developer, 개발자 김형준(Dip2K): 주어진-좌표와-선분-사이의-주어진-거리에-위치하는-선분의-좌표-구하기에 달린 최근 댓글/트랙백 목록</title>
		<link>http://www.gisdeveloper.co.kr/</link>
		<description></description>
		<language>ko</language>
		<pubDate>Fri, 30 Jul 2010 04:14:07 +0900</pubDate>
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		<title>G.I.S Developer, 개발자 김형준(Dip2K): 주어진-좌표와-선분-사이의-주어진-거리에-위치하는-선분의-좌표-구하기에 달린 최근 댓글/트랙백 목록</title>
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			<title>jjuiddong님의 댓글</title>
			<link>http://www.gisdeveloper.co.kr/527#comment8094</link>
			<description>큰 도움이 되었습니다. ^^;</description>
			<author>(jjuiddong)</author>
			<guid>http://www.gisdeveloper.co.kr/527#comment8094</guid>
			<comments>http://www.gisdeveloper.co.kr/527#comment</comments>
			<pubDate>Tue, 19 Jan 2010 13:30:14 +0900</pubDate>
		</item>
		<item>
			<title>김형준님의 댓글</title>
			<link>http://www.gisdeveloper.co.kr/527#comment8095</link>
			<description>별 말씀을, ^^ 댓글 감사합니다.</description>
			<author>(김형준)</author>
			<guid>http://www.gisdeveloper.co.kr/527#comment8095</guid>
			<comments>http://www.gisdeveloper.co.kr/527#comment</comments>
			<pubDate>Tue, 19 Jan 2010 16:26:51 +0900</pubDate>
		</item>
		<item>
			<title>준.님의 댓글</title>
			<link>http://www.gisdeveloper.co.kr/527#comment8104</link>
			<description>진행하는 프로젝트에 큰 도움이 되었네요. 고맙습니다.</description>
			<author>(준.)</author>
			<guid>http://www.gisdeveloper.co.kr/527#comment8104</guid>
			<comments>http://www.gisdeveloper.co.kr/527#comment</comments>
			<pubDate>Mon, 25 Jan 2010 16:10:12 +0900</pubDate>
		</item>
		<item>
			<title>김형준(Dip2K)님의 댓글</title>
			<link>http://www.gisdeveloper.co.kr/527#comment8105</link>
			<description>도움이 되었다니 좋습니다.</description>
			<author>(김형준(Dip2K))</author>
			<guid>http://www.gisdeveloper.co.kr/527#comment8105</guid>
			<comments>http://www.gisdeveloper.co.kr/527#comment</comments>
			<pubDate>Tue, 26 Jan 2010 11:34:42 +0900</pubDate>
		</item>
		<item>
			<title>유희진님의 댓글</title>
			<link>http://www.gisdeveloper.co.kr/527#comment8211</link>
			<description>음.. a, b가 x1과 y1과 같은경우의 공식을 다음과같이 산출했는데요..
그리고 ln 길이값을 알고 있는상태이구요
        douT = (douNextPoint(0) - douCurPoint(0)) ^ 2 + ((douNextPoint(1) - douCurPoint(1)) ^ 2) * (douCalLength) ^ 2
        douT = Abs(Sqr(douT)) / (douNextPoint(0) - douCurPoint(0)) ^ 2 + (douNextPoint(1) - douCurPoint(1)) ^ 2
        douX = douCurPoint(0) + douT * (douNextPoint(0) - douCurPoint(0))
        douY = douCurPoint(1) + douT * (douNextPoint(1) - douCurPoint(1))

음.. 제가 잘못 계산한듯한데요..</description>
			<author>(유희진)</author>
			<guid>http://www.gisdeveloper.co.kr/527#comment8211</guid>
			<comments>http://www.gisdeveloper.co.kr/527#comment</comments>
			<pubDate>Tue, 13 Apr 2010 14:50:20 +0900</pubDate>
		</item>
		<item>
			<title>유희진님의 댓글</title>
			<link>http://www.gisdeveloper.co.kr/527#comment8212</link>
			<description>dounextpoint(0)= x2 : dounextpoint(1) = y2
doucurpoint(0) = x1 : doucurpoint(1) = y1
입니다.  후움.. 공식상으로 맞는건지요???</description>
			<author>(유희진)</author>
			<guid>http://www.gisdeveloper.co.kr/527#comment8212</guid>
			<comments>http://www.gisdeveloper.co.kr/527#comment</comments>
			<pubDate>Tue, 13 Apr 2010 14:52:10 +0900</pubDate>
		</item>
		<item>
			<title>김형준님의 댓글</title>
			<link>http://www.gisdeveloper.co.kr/527#comment8216</link>
			<description>@_@;;;;; 댓글로 남긴 공식.. 저도 모가 뭔지 저도 모르겠습니다. douT뭐.. dounextpoint 며..</description>
			<author>(김형준)</author>
			<guid>http://www.gisdeveloper.co.kr/527#comment8216</guid>
			<comments>http://www.gisdeveloper.co.kr/527#comment</comments>
			<pubDate>Sun, 18 Apr 2010 00:41:24 +0900</pubDate>
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